The dimensional formula of impulse is
The correct answer is [MLT1].

Where Δp is change in momentum, F is force, and Δt is the time taken
EXPLANATION:
Impulse is given by:
\(Δ p=FΔ t\)
Impulse (J) \(= (m a)\:.t\) (1)
The dimensional formula for Force (ma) = M[L.T2] (2)
( \(\because\) a = velocity/time = \(\frac{dispalcement/time}{time}\) = \(\frac{L/T}{T}\) = L.T2 )
The dimensional formula for time (t) = T (3)
Substituting (2) and (3) in (1),
Dimension of Impulse = M[L.T2] × T = M1 L1 T1